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For `H_(alpha)`line of the balmer series `n_(1) = 2,n_(2) = 3`<br> For `H_(beta)`line of the balmer series `n_(1) = 2,n_(2) = 4`<br> `1/(lambda_(H_(alpha))) = R_(H) [(1)/(2^(2)) - (1)/(3^(2))]`……..(i) <br> ` and `1/(lambda_(H_(beta))) = R_(H) [(1)/(2^(2)) - (1)/(4^(2))]`……..(ii) <br> By equation (i) and (ii) we get <br> `:. (lambda_(beta))/(lambda_(alpha))= ((1)/(4) - (1)/(9))/((1)/(4) - (1)/(16))`<br> `:. lambda_(beta) = lambda_(alpha) xx [(80)/(108)] = 6500 xx (80)/(108) = 4814.8 Å`