# Find the value of ‘Req’ for the following circuit.

Find the value of ‘Req’ for the following circuit.

### Right Answer is:

14.4 Ω

#### SOLUTION

2Ω + (6 || 3)Ω

6 Ω and 3 Ω resistors are in parallel, equivalent resistance = **(6 × 3)/(6 + 3) = 2Ω**

2Ω + 2Ω = 4Ω

1 Ω and 5 Ω resistors are in series, equivalent resistance = 1 + 5 = 6 Ω

6Ω || 4Ω = **(6 × 4)/(6 + 4) = 2.4Ω**

4 Ω, 2.4 Ω and 8 Ω resistors are in series.

Equivalent resistance (R_{eq}) = 4 + 2.4 + 8 = 14.4 Ω